POLYNOMIALS

 

Polynomials are expressions with more than one term, such as

 

3x + 2y

+ 8x - 9

 

We call an expression with two terms, like 3x + 2y, a "binomial."

 

 

MULTIPLYING POLYNOMIALS

 

To multiply two algebraic expressions, multiply every term in the first expression by every term in the other expression.

 

Example:  3x (5x + 2y - z)

=(3x)(5x) + (3x)(2y) - (3x)(z)

=15+ 6xy - 3xz

 

Example:  (a + b)(c + d) = ab + ad + bc + bd

 

When we multiply two binomials we use the FOIL method.  FOIL stands for "First Outer Inner Last" and is a way to remember to multiply the

First terms (a x c)

Outer terms (a x d)

Inner terms (b x c)

Last terms (b x d)

 

Example:  (a + 2)(a - 5) =  - 5a + 2a - 10 =  - 3a -10

 

Example: = (x + y)(x + y)

= + xy + yx +

= + xy + xy +  

= + 2xy +

 

Caution:  is NOT the same as +  (This is a very common error!)

 

 

VERY IMPORTANT EQUATIONS

 

The following relationships are very important and should be memorized.

 

I.  =  + 2xy +

II.  =  - 2xy +

III.  (x + y)(x - y) =  -  (This is called the "difference of squares" since  and y2 are squares and  -  is the difference of two squares.)

 

Example: =+ 2(3x)+ = + 6x + 9

 

Example:  (a + 2)(a - 2)= - 4

 

 

FACTORING POLYNOMIALS

 

To factor polynomials we do the reverse of multiplication.

 

Example:  Factor 15 - 35xy 

Solution:  Look for a common numerical factor and look for a common factor with a variable.  Since 15 and 35 are both divisible by 5, 5 is a common factor of both terms.  Since  and xy are both divisible by x, x is a common factor of both terms. 

Therefore, 15- 35xy = 5x(3x - 7y)

 

Example:  Factor - 25

Solution:  and 25 are both squares, so  - 25 is the difference of squares.  Therefore  - 25 = (x + 5)(x - 5).

 

 

SOLVING EQUATIONS WITH POLYNOMIALS

 

If A and B are two numbers and if AB = 0, then either A = 0 or B = 0.  To solve equations where polynomials are equal to zero, we factor the polynomial and set each factor equal to 0 and solve.

 

Example: - 6x = 0

Since - 6x = x(x - 6) we can find values of x which satisfy the equation by setting x = 0 and x - 6 = 0.  Therefore, x = 0 or +6.

 

Check:   3 - 6(0) = 0 + 0 = 0

- 6(6) = 36 - 36 = 0.

 

Example:  - 25 = 0

We wish to find values of x that will make the equation a true statement.  The trick is to factor  - 25 and set each factor equal to 0.

 - 25 = 0

(x + 5)(x - 5) = 0

Therefore, x + 5 = 0 means that x = -5

and x - 5 = 0 means that x = +5. 

Therefore, there are two solutions, x = 5, and x = -5.